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1 solution
let ao and bd intersect at a point l.then if we reconstruct the arms al and bl into a parallelogram,through similarity we can compare the products as follows: Y(AB X BD)=OD X OA. where y is a scale constant. we know that AO X OD=9 and by differentiating the following result with any length parameter 'K' we can conclude that (AB X BD)y=constant hence we know that AB X BD is constant for any given values of AB,BD which is =9 ie 3 X 3;hence we prove that the product is constant for a given circle of given radius.For this it is =9