Quadrilateral is circumscribed about a circle , that is tangent to at respectively. Suppose that and intersect at point and and intersect at point . If , what is the distance between and
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First, "hexagon" AEBCGD is circumscribed about I, since all 6 of its sides are tangent. Thus, by Brianchon's Theorem, AC, EG, and BD all concur. Since AC and BD intersect at P, we have that EG passes through P. Similarly, by Brianchon's Theorem on ABFCDH, we have that FH passes through P as well. Therefore, EG and FH intersect at P, so P and Q are the same point.