◢Circumscribed Triangle◣

Geometry Level 2

Given that segments A C = C B AC = CB and point C C is the circle's center, find the area of the blue region.

Round answer to the nearest hundredths


The answer is 66.04.

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2 solutions

area of blue region = area of the circle - area of the triangle \text{area of blue region = area of the circle - area of the triangle}

area of blue region = π r 2 1 2 b h = π ( 5 2 ) 1 2 ( 5 ) ( 5 ) 66.040 \text{area of blue region} = \pi r^2 - \dfrac{1}{2}bh = \pi (5^2) - \dfrac{1}{2}(5)(5) \approx \boxed{66.040}

Brack Harmon
Mar 19, 2018

To find the area, subtract out the area of the triangle from 1 4 \frac{1}{4} of the circular area, Then add 3 4 \frac{3}{4} of the area of the circle.

A r e a = 1 4 π Area = \frac{1}{4}π · 5 2 5^2 - 5 2 2 \frac{5^2}{2} + 3 4 π \frac{3}{4}π · 5 2 5^2 66.0398 \boxed{66.0398}

Or just subtract the triangle of the circle at once ;)

Peter van der Linden - 3 years, 2 months ago

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You're right, that's much simpler

Brack harmon - 3 years, 2 months ago

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