Circumsphere

Geometry Level 4

The radius of the smallest sphere that contains all four points ( 0 , 0 , 0 ) , ( 8 , 0 , 0 ) , ( 0 , 10 , 0 ) , ( 0 , 0 , 14 ) (0,0,0) , (8,0,0) , (0,10,0), (0,0,14) can be expressed as m n m \sqrt{n} , where n n is not divisible by the square of any prime. Find m + n m+n .


The answer is 13.

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1 solution

Albert Wen
Nov 23, 2015

This radius is the same as the radius of the circumscribed sphere of the tetrahedron with vertices at the given points. Then, we realize that the circumcenter of this tetrahedron must lie on the lines perpendicular to the faces at the circumcenters of those faces. Because some of the faces are right triangles, it is simple to find that the circumcenter is (4,5,7). Then, we find the radius by the Pythagorean Theorem. We thus get that r = 3 10 3 \sqrt{10} , and 3+10 = 13.

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