cirlces!!!
AB
is a line segment of length
4 cm
.
P
is the mid-point of AB. Circles are drawn with
A
,
P
and
B
as centres and radii
AP
=
PB
(see figure) and D and C lie on the circles. The area of the shaded portion (in
) is:
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
1 solution
In this question, area of the shaded region = Ar. semicircle - Ar. trapezoid ABCD. If we join DP and CP, we get 3 equilateral triangles with side = 2. Therefore area of trapezium ABCD = 3 \times \sqrt(3) \times 2^{2} \times 0.25 = 3\sqrt(3)
Therefore area of the shaded region = Area of the semicircle - 3\sqrt(3) = \boxed{2π - 3\sqrt(3)}