Clash of the Tennis Titans

Roger Federer and Rafael Nadal are playing a tennis match.

It is Roger's serve.

Because he is serving (and the server usually has an edge over the receiver), Roger's odds of winning a point are 2 : 1 2:1 in his favour.

Find the probability that Roger wins his service game. Round your answer off to 3 decimal places.

Details about Tennis Scoring \textbf{Details about Tennis Scoring}

  • For those who are not acquainted with tennis, the scoring is explained on this page . Briefly, the game scoring (the scoring that concerns us in this problem) is as follows

  • 0 0 is also called "love" in tennis.

  • Examples of scores - 0 0 , 0 30 , 40 15 0-0, \ 0-30, \ 40-15 etc.

  • 40 40 40-40 is called Deuce .

  • Once at deuce, a player must win 2 consecutive \textbf{2 consecutive} points to take the game.

  • If Player A A wins the deuce point \textbf{wins the deuce point} , then the score is Advantage Player A \textbf{Advantage Player A} .

  • If, after gaining advantage, the player looses the next point \textbf{looses the next point} , then the score comes back to deuce \textbf{back to deuce} .

  • In all the points that concern us, Roger serves as they are all part of the same Federer service game.

  • This is a completely hypothetical scenario.


The answer is 0.855967.

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1 solution

Pop Wong
May 17, 2020

The possible scenario Rogor won the game:

Federer Nadal Next Scenario Pr Note
40 0 Federer win next pt Pr = ( 2 / 3 ) 3 ( 2 / 3 ) (2/3)^{3} *(2/3) 144 729 \frac{144}{729}
40 15 Federer win next pt Pr = 4 C 1 ( 2 / 3 ) 3 ( 1 / 3 ) ( 2 / 3 ) 4C1 (2/3)^3 (1/3) * (2/3) 192 729 \frac{192}{729}
40 30 Federer win next pt Pr = 5 C 2 ( 2 / 3 ) 3 ( 1 / 3 ) 2 ( 2 / 3 ) 5C2 (2/3)^3 (1/3)^2 * (2/3) 160 729 \frac{160}{729}
40 40 Federer win the deduce with Pr= P d P_d Pr= 6 C 3 ( 2 / 3 ) 3 ( 1 / 3 ) 3 6C3 (2/3)^3(1/3)^3 * P d P_d 160 729 \frac{160}{729} * P d P_d

P d P_d = Pr(Roger wins next two pt) + Pr(Re-deduce) * P d P_d

P d P_d = ( 2 / 3 ) ( 2 / 3 ) + 2 ( 2 / 3 ) ( 1 / 3 ) (2/3)(2/3) + 2(2/3)(1/3) * P d P_d

P d P_d = 4 9 \frac{4}{9} * 9 5 \frac{9}{5} = 4 5 \frac{4}{5} ; you may calculate P d P_d by G.P.

Pr(Roger win) = 144 729 \frac{144}{729} + 192 729 \frac{192}{729} + 160 729 \frac{160}{729} + 160 729 \frac{160}{729} * 4 5 \frac{4}{5} = 144 + 192 + 160 + 128 729 \frac{144+192+160+128}{729} = 624 729 \frac{624}{729} = 0.855967

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