There are 10 girls in a mixed class.
If two pupils from the class are selected at random, then the probability that both are girls is 0.15
How many boys are in the class?
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Let the number of boys in the class be x.
Hence 1010+x×99+x=0.15=320.
Simplifying gives 1800=3(10+x)(9+x) and then x2+19x−510=0.
Factorising gives (x+34)(x−15)=0 and, since x≠−34, x=15.
Alternatively, let the number of students in the class be x.
Hence 10x×9x−1=0.15=320.
Simplifying gives 600=x(x−1) and then x2−x−600=0.
Factorising gives (x+24)(x−25)=0 and, since x≠−24, x=25.
Therefore the number of boys in the class is 15.