Classroom Confusion!

Algebra Level 2

There are 10 girls in a mixed class.

If two pupils from the class are selected at random, then the probability that both are girls is 0.15

How many boys are in the class?

23 12 63 15

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Surayyah Aziz
May 19, 2019

Let the number of boys in the class be x.

Hence 1010+x×99+x=0.15=320.

Simplifying gives 1800=3(10+x)(9+x) and then x2+19x−510=0.

Factorising gives (x+34)(x−15)=0 and, since x≠−34, x=15.

Alternatively, let the number of students in the class be x.

Hence 10x×9x−1=0.15=320.

Simplifying gives 600=x(x−1) and then x2−x−600=0.

Factorising gives (x+24)(x−25)=0 and, since x≠−24, x=25.

Therefore the number of boys in the class is 15.

Roger Erisman
May 19, 2019

Let number of boys equal B.

First choice is girl = 10/(10+B).

Second choice is girl = 9/(9+B).

Multiply: (10x9)/((10+B)*(9+B))= 0.15

Simplify: 90/0.15 = (10+B) (9+B) = B^2 + 19 B+ 90 = 600

Solve: B^2 + 19*B- 510 = 0

Factoring: (B+34)*(B-15) = 0

So B= -34 or B= 15. We can disregard the negative answer, B= 15.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...