Cleaning up the equipment

Relevant wiki: Identical Objects into Identical Bins

This can be modeled as the number of partitions of $n=8$ into exactly $r=4$ parts.

This is equivalent to $p(8,4)$ , the number of partitions of $8$ for which $4$ is the largest part. With $4$ as the largest part, there is $4$ left to be partitioned. $p(4)=5$ , so there are $\boxed{5}$ ways to distributed the bats.

Incidentally, the partitions of $8$ into exactly 4 parts are: $5+1+1+1$ $4+2+1+1$ $3+3+1+1$ $3+2+2+1$ $2+2+2+2$

There are the same number of partitions of $8$ for which $4$ is the largest part: $4+4$ $4+3+1$ $4+2+2$ $4+2+1+1$ $4+1+1+1+1$