Clever boy
Ashish, while posting a question thought that giving four options, the solver will easily predict the answer. So, in order to make the question tough, he threw an unbiased dice. And whatever number appeared, was multiplied by the four options making some additional set of options.
For an explicit example, if 3 appeared on the dice, then ashish gave (4×3=12 options).
If it is known that an even number appeared on the dice then what is the probability that you will get 16 options.Give your answers by rounding of to two decimal places.
If you think this is an impossible scenario then enter 777 as the answer.
The answer is 0.33.
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1 solution
Thanks Abhay ;) That is exactly how I think.
Only 3 numbers can appear namely 2,4 and 6, because rest are odd. Then their corresponding options are 2×4, 4×4, 6×4 = 12,16,20. So, the probability of getting 12 is 1/3 = 0 . 3 3