Clock Angles - 1

My idea of solution:

Each marker on the clock is equivalent to 6º (360º/60 minutes = 6º). So, from 45 minutes to 46 minutes we have $\boxed{6º}$ . Then, from 6 hours to 9 hours we have $\boxed{90º}$ (the minute hand is after 9 hour marker and the hour hand is before 6 hour marker). Then we have to calculate the position of the hour hand (as we know, the hour hand shifts accordingly to the amount of minutes passed). From 5 hours to 6 hours we have 5 markers, or so, $\boxed{30º}$ . Within the hour 4, we have 5 markers too.To know the exact proportion, we can do the following rule of three (knowing that 46 minutes are equivalent to 276º):

$\frac{360º}{276º} \times \frac{30º}{x}$ $x = \frac{8280}{360}$ $x = 23º$

So, we subtract 23 from 30 and we get $\boxed{7º}$ remaining to 5 hours.

Adding them all up:

$6º + 90º + 30º + 7º = \boxed{133º}$

But then what I did was wrong could some one tell me where I'm thinkin' wrong here:

1min=6 degrees 4 corresponds to 20 minutes thus 46-20=26 and therefore 26*6=156