Close Enough to Ramanujan's Favorite

Algebra Level 2

If 4 log 12 ( x 9 ) + log 12 ( x 6 ) = 126 4 \log_{12} \left(x^9\right) + \log_{12} \left(x^6\right) = 126 , find x . x.


The answer is 1728.

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6 solutions

Noel Lo
May 5, 2015

4 log 12 x 9 + log 12 x 6 = 126 4 \log_{12} x^9 + \log_{12} x^6 = 126

36 log 12 x + 6 log 12 x = 126 36 \log_{12} x + 6 \log_{12} x = 126

42 log 12 x = 126 42 \log_{12} x = 126

log 12 x = 3 \log_{12} x = 3

x = 1 2 3 = 1728 x = 12^3 =\boxed{1728}

Piyush Nanda
May 7, 2015

Moderator note:

Right. Bonus question: What does the title mean when it says "Close enough to Ramanujan's favourite"?

I think that Ramnujan's favorite number is 1729!

Hobart Pao - 6 years, 1 month ago

Dear Challenge Master, Ramanujan's favourite number is 1729. As you can see, many questions on Brilliant involve the number 1729. The answer to this question is 1728, just 1 less than 1729, hence the title!!

Noel Lo - 6 years, 1 month ago

Now only I know what's Ramanujan's number...

Hon Ming Rou - 5 years, 11 months ago

Both Noel and Piyush did the same, but why did Noel has a 6 times more upvotes. Still confused. Ha ha !!!! Just for fun!!!!

Prayas Rautray - 3 years, 11 months ago
Huzaifa Raghav
May 10, 2015

4log12 x^9 + log12x^6=126

36log12 x + 6log12x=126

42log12 x=126

log12 x= 3

x=12^3=1728

Shaban Alshaba
May 6, 2015

4x9logx+ 6log x=42 log x =126 Log12 (x) =126/42 =3 3 X=12. =1728

Paola Ramírez
May 6, 2015

4 log 12 x 9 + log 12 x 6 = 126 4 \log_{12} x^9 + \log_{12} x^6 = 126

36 log 12 x + 6 log 12 x = 126 36 \log_{12} x + 6 \log_{12} x = 126

42 log 12 x = 126 42 \log_{12} x = 126

log 12 x = 3 \log_{12} x = 3

x = 1 2 3 = 1728 x = 12^3 =\boxed{1728}

Exactly the same as mine haha!

Noel Lo - 6 years, 1 month ago
Kenneth Gibson
May 12, 2015

Ramanujan's favorite is 1729 = 10^3 + 9^3 = 1^3 + 12^3. 1728 = 10^3 + 9^3 - 1^3 = 12^3

wtf wtf wtf. Z.😠😠😠😠😠😠😠😠

Am Kemplin - 1 month, 2 weeks ago

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