Close to √n

Algebra Level 2

f ( n ) = 2 n ˉ + 2 n ˉ 2 n \large f(n) = \frac {2^{\bar n}+2^{-\bar n}}{2^n}

Let f ( n ) f(n) be defined as above for all positive integer n n , where n ˉ \bar n is the nearest integer to n \sqrt n .

What is the value of f ( 1 ) + f ( 2 ) + f ( 3 ) + f(1)+f(2)+f(3) + \cdots ?


The answer is 3.

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1 solution

Alapan Das
Mar 25, 2019

If k is a positive integer such that k=ñ then k²-k+1≤n≤k²+1. Then we put the values of k and respective n s in the summation. Now, for a k, ñ=k . And n varies over the integers of the set {k²-k+1,k²+1}. As n varies from 1 to infinity k also varies from 1 to infinity. Then we get S=3

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