Coefficient play

The number of terms in the expansion of ( 3 x 4 y + 6 z ) 4 (3x-4y+6z)^4 is m m and the coefficient of x y 2 z xy^2z in the same expansion is n n . Find m + n m+n .


The answer is 3471.

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1 solution

Akshay Yadav
Feb 7, 2016

Multinomial theorem plays its role here.

First we need to find the number of terms in expansion ' m m ',

Here,

k k = Number of terms in polynomial

n n = Power of expansion

m = ( n + k 1 n ) m=\dbinom{n+k-1}{n}

m = ( 6 4 ) m=\binom{6}{4}

m = 15 m=15

Now,

We need to calculate the coefficient of x y 2 z xy^2z ,

General term for expansion of ( 3 x 4 y + 6 z ) 4 (3x-4y+6z)^4 will be 4 ! a ! b ! c ! ( 3 x ) a ( 4 y ) b ( 6 z ) c \frac{4!}{a!b!c!}(3x)^a(-4y)^b(6z)^c ,

Pluging in the values a = 1 a=1 , b = 2 b=2 and c = 1 c=1 and we get 3456 x y 2 z 3456xy^2z

Hence,

n = 3456 n=3456

So,

m + n = 3471 m+n=\boxed{3471}

Nice solution !

Akshat Sharda - 5 years, 4 months ago

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Thanks brother!

Akshay Yadav - 5 years, 4 months ago

Can you explain to me where will I use ( n + k 1 n 1 ) \dbinom{n + k - 1}{n - 1} for calculating the number of terms of an expansion with the same use of variables as yours? source

Reineir Duran - 5 years, 4 months ago

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Sorry, but I am not able to understand your question.

Akshay Yadav - 5 years, 4 months ago

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