Codes

Add 1 to every letter in the word 'CORE' which comes out to be 'DPSF'

In each one of rhe words the letters of another word is added to1 . So c+1, o+1, r+1, e+1 , will be equal to dpsf

K = k+1 so A=B

You could easily get the answer my checking at what letters are already translated. E->F and if you check the choices, no other choice contains F as the last letter. So DPSF

This problem is very simple-just turn the letters into their numerical counterparts (for example, A=1, B=2...) and look for a pattern. Soon you will find that you can code these words by adding one to their numerical value-for example, E becomes F, T becomes U, etc. Therefore if you apply this knowledge to the word CORE you get DPSF.

It's a simple Cesar's code, where the key is 1.... so you increment in the alphabet the amount of caracters of the key :)

only see that O~P E~F and check the MC

Looking at the two examples, I can see it's a Caesar cipher, where the key is 1. Therefore, CORE = DPSF because C -> D, O -> P, R -> S and E -> F.

DPSF x=x=1; a=b

If 'x' is a character, you have to choose the character next to it.

Just take the following word of the word to be encoded. Like A=B, B=C, C=D, D=E, E=F, F=G, G=H, H=I, I=J.......Z=A

It is simply next alphabet,hece CORE will be coded as DPSF Ans K.K.GARG,India

Next alphabet of each alphabet