Let be the coefficient of in the expansion of . Determine the value of where is a positive integer.
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When x=1 , coefficient of x^2 = 2c2 = 1
When x=2 , coefficient of x^1 = 3c2 = 3
When x=3 , coefficient of x^0 = 4c2 = 6
When x=4 , coefficient of x^-1 = 5c3 = 10
When x=5 , coefficient of x^-2 = 6c4 = 15
When x=6 , coefficient of x^-3 = 7c5 = 21
Here you can see that for x = n u m , the coefficient is sum of first n u m natural numbers.
So when x = 7 , the coefficient = 8 c 6 = 8 ∗ 7 / 2 = 2 8
General term for the reciprocal A 1 n = n ( n + 1 ) / 2 1
General term A 1 n = 2 ( n 1 − n + 1 1 )
The sum = 2 ( ( 1 1 − 2 1 ) + ( 2 1 − 3 1 ) + ( 3 1 − 4 1 ) + … − ∞ 1 ) = 2 ∗ 1