What is the coefficient of in the expansion of
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Notice that there are 18 terms in the given problem. Therefore, an x 1 7 term would have to be multiplied out by 17 of the expansions to give x 1 7 , while the final one provides its numeric value.
The terms that would come are : − 1 x 1 7 − 2 x 1 7 − 3 x 1 7 . . . . − 1 8 x 1 7 − ( 1 + 2 + 3 + . . . 1 7 + 1 8 ) x 1 7 − 1 7 1 x 1 7