Coefficient trouble?

What is the coefficient of x 17 x^{17} in the expansion of ( x 1 ) ( x 2 ) . . . ( x 17 ) ( x 18 ) (x-1)(x-2)...(x-17)(x-18)


The answer is -171.

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2 solutions

Vishnu Bhagyanath
May 21, 2015

Notice that there are 18 terms in the given problem. Therefore, an x 17 x^{17} term would have to be multiplied out by 17 of the expansions to give x 17 x^{17} , while the final one provides its numeric value.

The terms that would come are : 1 x 17 2 x 17 3 x 17 . . . . 18 x 17 -1x^{17} -2x^{17} -3x^{17} .... - 18x^{17} ( 1 + 2 + 3 + . . . 17 + 18 ) x 17 -(1+2+3+...17+18) x^{17} 171 x 17 -171x^{17}

Nice solution.But coefficients are classified in combinatorics aren't they?

Arian Tashakkor - 6 years ago

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I've changed the topic, thanks! :)

Vishnu Bhagyanath - 6 years ago

Let p(x) = above expression , then by Vieta's Formula , coefficient of x^17 = -(sum of roots of polynomial) = -(1+2+3....+18) = -18*19/2 = -171

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