Coefficients Party, Part 1

Algebra Level 3

Find the coefficient of the x 2 y 6 x^2y^6 term in the expansion of ( 3 x 2 y ) 8 . (3x-2y)^8.


The answer is 16128.

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3 solutions

Jubayer Nirjhor
May 4, 2014

By Binomial Theorem, the answer is: ( 8 2 ) 3 2 ( 2 ) 6 = 16128 \dbinom{8}{2}\cdot 3^2\cdot (-2)^6=\fbox{16128}

ur answer is right but the 8C6 comes instead of 8C2.

Harsh Bhavsar - 7 years, 1 month ago

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( 8 6 ) = ( 8 2 ) \dbinom{8}{6}=\dbinom{8}{2}

( 8 6 ) = 8 ! 6 ! × ( 8 6 ) ! = 8 ! 6 ! 2 ! \dbinom{8}{6}=\frac{8!}{6!\times(8-6)!}=\frac{8!}{6!2!}

( 8 2 ) = 8 ! 2 ! ( 8 2 ) ! = 8 ! 2 ! 6 ! = 8 ! 6 ! 2 ! \dbinom{8}{2}=\frac{8!}{2!(8-2)!}=\frac{8!}{2!6!}=\frac{8!}{6!2!}

Therefore,

( 8 6 ) = ( 8 2 ) \dbinom{8}{6}=\dbinom{8}{2}

In general,

( n r ) = ( n n r ) \dbinom{n}{r}=\dbinom{n}{n-r}

Alex Segesta - 7 years, 1 month ago

both are same

Prajwal Kavad - 7 years ago

Binomial Theorem? Can you tell me more about that, please? I don't know anything about that.

Selene (Elly) Kirkland - 7 years, 1 month ago

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See here: http://www.artofproblemsolving.com/Wiki/index.php/Binomial_Theorem

Hahn Lheem - 7 years, 1 month ago

it is a theorem used for finding expansions of expressions having very high exponents.

ishan pradhan - 6 years, 7 months ago
Leonhard Euler
May 9, 2014

Taking for granted that ( a + b ) n = k = 1 n ( n k ) a n k b k (a + b)^n = \sum_{k=1}^n {n \choose k}a^{n-k} b^k

From the problem we see that n = 8 , a = 3 x , b = 2 y n = 8, a = 3x, b = -2y

Substituting and carrying out the computation will give the correct answer. A great first look on the binomial theorem is the following book

https://archive.org/details/philtrans01793630

Good explain... you should continue...

Heder Oliveira Dias - 7 years, 1 month ago
Pragya Singhal
May 6, 2014

using binomial expansion to solve the problem, STEP 1 :- (3x-2y)^8 STEP 2 :- {c(8,2)} x {(3)^2} x {(-2)^6} STEP 3 :- 16128

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