Find the coefficient of the x 2 y 6 term in the expansion of ( 3 x − 2 y ) 8 .
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ur answer is right but the 8C6 comes instead of 8C2.
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( 6 8 ) = ( 2 8 )
( 6 8 ) = 6 ! × ( 8 − 6 ) ! 8 ! = 6 ! 2 ! 8 !
( 2 8 ) = 2 ! ( 8 − 2 ) ! 8 ! = 2 ! 6 ! 8 ! = 6 ! 2 ! 8 !
Therefore,
( 6 8 ) = ( 2 8 )
In general,
( r n ) = ( n − r n )
both are same
Binomial Theorem? Can you tell me more about that, please? I don't know anything about that.
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See here: http://www.artofproblemsolving.com/Wiki/index.php/Binomial_Theorem
it is a theorem used for finding expansions of expressions having very high exponents.
Taking for granted that ( a + b ) n = k = 1 ∑ n ( k n ) a n − k b k
From the problem we see that n = 8 , a = 3 x , b = − 2 y
Substituting and carrying out the computation will give the correct answer. A great first look on the binomial theorem is the following book
https://archive.org/details/philtrans01793630
Good explain... you should continue...
using binomial expansion to solve the problem, STEP 1 :- (3x-2y)^8 STEP 2 :- {c(8,2)} x {(3)^2} x {(-2)^6} STEP 3 :- 16128
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By Binomial Theorem, the answer is: ( 2 8 ) ⋅ 3 2 ⋅ ( − 2 ) 6 = 1 6 1 2 8