Coin Toss

I made a machine which can toss coin at exactly same force every time.

I observed that in each toss the coin completes 25 rotation taking total time of 3706 milliseconds.

Coin looses its force at 4% after completing each rotation.

What time (in milliseconds) is taken by coin to complete first rotation..??

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1 solution

Aaditya Bhatt
Jul 11, 2014

Assume that first rotation completes in 100 milliseconds.

When coin completes second rotation it will loose its 4% force and time will increase by 4 milliseconds completing second rotation in 104 seconds. and so on.

So theoretically after 25 rotations you will require 4164 milliseconds.

Compare assumption with actual total time.

i.e. for total 4164 milliseconds first rotation completed in 100 milliseconds then how many milliseconds will it take when total time is 3706 milliseconds.

Answer will be 89 Milliseconds.

when we toss a coin we apply impulsive force to it, so angular velocity = impulsive force/ inertia. Now if force is decreasing by 4% then even angular velocity will decrease by 4%. 1 rotation = 2*pi radians =w1 *t1= w2 *t2= w3 *t3, ...and so on or w1 *t1 = 0.96w1 *t2= 0.92w1 *t3, (or) t2= t1/0.96, t3= t1/0.92, etc. Finally we get a Harmonic progression which i don't know how t solve.

Rahul Badenkal - 6 years ago

In other words if time for 1st rotation is 100 milliseconds then time for 2nd rotation should be 100/0.96 = 104.116 milliseconds

Rahul Badenkal - 6 years ago

how can gravity change the rotation rate. gravity is central forces so it can,t change the rate of rotation.it can change only the velocity of the coin.

Hare Krishna Physics - 6 years, 11 months ago

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Did I mentioned anywhere that due to effect of gravity the rotation rate is changed.??

Aaditya Bhatt - 6 years, 11 months ago

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