Coins !

if you flip 10 unbiased coins simultaneously find the probability of getting atleast 1 heads. Then let your probability be a/b which is coprime . multiply a/b by 4/3 - and after doing this add the numerator with the denominator.


The answer is 597.

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2 solutions

P (x)= 1-P (not x) Coins'tossing has 2 outcomes and number of tosses is 10 thus 2^10 is the total event number. P (Atlest 1head) = 1-P (all tail) Only in one case all tail occurs thus 1-1/1024 =1023/1024 Rest I guess you can manage!

Palash Som
Dec 29, 2014

The question is really easy we just need to manipulate it .

see we can manipulate it as = P ( of not occuring all tails ) and since all tails would

occur only once hence - P(of not occuring all tails) = 2^10 -1 / 2^10=1023/1024

so 1023/1024 * 4/3 = 341 / 256 so - 341 +256 = 597

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