if you flip 10 unbiased coins simultaneously find the probability of getting atleast 1 heads. Then let your probability be a/b which is coprime . multiply a/b by 4/3 - and after doing this add the numerator with the denominator.
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P (x)= 1-P (not x) Coins'tossing has 2 outcomes and number of tosses is 10 thus 2^10 is the total event number. P (Atlest 1head) = 1-P (all tail) Only in one case all tail occurs thus 1-1/1024 =1023/1024 Rest I guess you can manage!