COINS
Level
pending
IN A GROUP OF 50, 25, & 10 CENTAVO COINS THE TOTAL NUMBER OF COINS IS FOUR TIMES OF THE TOTAL AMOUNT. CONSIDERING THE LEAST NUMBER OF COINS,HOW MANY 25 CENTAVO COINS ARE THERE IN THE GROUP?
The answer is 4.
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1 solution
Let x be the number of 50 centavo coins Let y be the number of 25 centavo coins Let z be the number of 10 centavo coins
X+y+z = (.50x+.25y+.10z)4
X+y+z =2x+y+.40z
X= .60z
Consider x= 3 then y= 5 for least number of coin
And y= 4
3+4+5=12 (number of coins)
Then the amount is .50×3 +.25×4 +.10×5 Amount=3
So the number of coins is four times of the total amount