There are 4 boxes, each with a label and each with either, silver, gold, or both silver and gold coins. Exactly 2 boxes have mixed coins, exactly one box has all gold, and exactly one box has all silver. Two of the labels are false and two are true.
Box 1: Box 2 has a mix of gold and silver.
Box 2: Box 3 has all silver.
Box 3: Box 4 has all gold.
Box 4: Box 1 has all silver.
Which boxes contain mixed coins?
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Assume that box 1 and 4 lie. Then boxes 2 and 3 have correct labels. Then silver is in 3 and gold is in 4. But box 1 has a false label and therefore box 2 has either all silver or all gold. We have a contradiction. Then either box 1 or 4 (or both) have a correct label.
Suppose now 2 and 4 lie. Then 3 told the truth (and 1). Then 4 has gold. But silver is not in 3 because 2 lied, and silver is not in 1 because 4 lied. Also, silver is not in 2 because 2 would have mixed. Then silver is in 4. This is a contradiction.
We then have that 2 or 4 tells the truth. Notice that 2 and 4 cannot be true at the same time. Since so far our options for true labels are 1, 2, or 4, and since there are 2 true labels, for sure 1 is true. This means that 2 has mixed coins. Moreover, there is a true label between 2 and 4. Thus, box 3 has a false label since there are 2 false ones, 1 is true, and one between 2 or 4 is true.
Since 3 lies, box 4 does not have all gold. But since 2 or 4 tells the truth, silver is in 3 or 1, that is, silver is not in 4. Then 4 also has mixed coins.