Which of the followings are true for any bounded sequences { a n } , { b n } of real numbers?
A . B . C . n → ∞ l i m s u p a n = n → ∞ l i m s u p a 3 n . n → ∞ l i m s u p ( a n + b n ) = n → ∞ l i m s u p a n + n → ∞ l i m s u p b n . n → ∞ l i m s u p ( a n + 1 − a n ) = 0 .
This is a part of the College Calc problem set. You can find more problems here .
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Oh, I confused bounded with convergent and proved all of them true. Seeing the answer None of them, I was like wait, wtf??!!
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A. False
Consider the sequence { a n } : = 3 , 2 , 1 , 3 , 2 , 1 , 3 , 2 , 1 , ⋯ . We have
n → ∞ l i m s u p a n = 3 ; n → ∞ l i m s u p a 3 n = 1 .
B. False
Consider the sequences { a n } : = 1 , 2 , 1 , 2 , 1 , 2 , ⋯ and { b n } : = 2 , 1 , 2 , 1 , 2 , 1 , ⋯ . We have
n → ∞ l i m s u p a n = n → ∞ l i m s u p b n = 2 ; n → ∞ l i m s u p ( a n + b n ) = 3 .
C. False
Consider the sequence { a n } : = 0 , 1 , 0 , 1 , 0 , 1 , ⋯ . We have that { a n + 1 − a n } = 1 , − 1 , 1 , − 1 , 1 , − 1 , ⋯ , such that
n → ∞ l i m s u p ( a n + 1 − a n ) = 1 .