A ball moving with constant velocity strikes a stationary ball Both balls continue on in a collinear motion.
What can be said about the total kinetic energy of the system comprising of both balls and
Assume that the balls are of equal masses.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Let the Initial velocity of ball A be equal to V Let the Final velocity of Ball A and Ball B after collission be equal to V1 and V2 respectively.
Since momentum is conserved m V = m V1 + m*V2. Therefore V = V1+V2.
So let us compute initial Kinetic Energy as 0.5 m V^2
Final Kinetic Energy = 0.5m*(V1^2 + V2^2)
Since V = V1 + V2, initial kinetic energy can be written as 0,5 m (V1 + 2) ^ 2.
It can be very easily seen that the final Kinetic energy is greater than the initial kinetic energy by m V1 V2 and so the total energy of the system after collission reduces.