A Smooth Tunnel Is Dug Along The Radius Of Earth That Ends At The Centre Of Earth . A Ball Is Released From the surface of earth along the tunnel . coefficient of restitution for collision between soil at the centre and ball is 0.5 . Calculate The Total Distance Travelled By Ball Just Before Second Collision At Centre Of Earth .
Details And Assumptions
You Need To Calculate The Distance travelled by the ball from the instant it is released from the surface of earth to the instant when it collides with the centre of earth second time
The Ball Is Quite Small In Comparison To Earth
The Width Of The Tunnel Is Sufficient For the ball to travel through it smoothly.
Take
Radius Of Earth = 6400 km
Mass Of Earth = 6*10^24 kg
Mass Of Particle = 10 kg
Report The Answer In km(kilometres)
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Total distance comes out to be R+(R/2*2)= 2R=12800 km