collision
If an object is dropped from a height of m towards a horizontal surface with coefficient of restitution . Then the time in seconds before object comes to rest after successive collision with the surface is
The answer is 6.
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1 solution
with each collision the speed becomes (ev). using v = u + at, we get t1=v/g, t2=2ev/g and so on. now when we add them, we get T = t1 + t2 + + ....... = v/g + 2ev/g + (2e^2v)/g + .......... = v/g + (2ev/g)*( 1 +e + e^2 + ........) whic implies T = 2 + 4 = 6s