Colorful Dice 2

Probability Level 1

You have three 6-sided dice. One is red, one is blue, and one is green. What is the probability that you will roll a 1 on the red die, a 2 on the blue die, and a 3 on the green die?

\frac{1}{3}

\frac{1}{216}

\frac{1}{36}

\frac{1}{6}

1 solution

Karleigh Moore
Apr 20, 2016

Using the rule of product , we know there are 216 possible combinations of rolls for the three colorful dice. Since having the red die=1, the blue die=2, and the green die=3, that is one of the 216 combinations. You can also think of it this way: there is a 1/6 probability that the red die will be 1, a 1/6 probability that the blue die will be 2, and a 1/6 probability that the green die will be 3. $\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{216}$

Colorful Dice 2

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