Coloring the integers

What is the minimum number of consecutive positive integers you need such that, if you color each integer with one of two colors, three integers of the same color will necessarily form an arithmetic progression?


The answer is 9.

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1 solution

Frank Aiello
Jul 31, 2017

The answer is 9. This a consequence of van der Waerden's theorem, which states: if N = A 1 . . . A k N = A_1 ∪ ... ∪ A_k is a partition of the sets of N, then one of the sets A 1 , . . . , A k A_1, ..., A_k contains finite arithmetic progressions of arbitrary length. Given positive integers m m and l l , there is a positive integer m m such that if the set {1, 2, ..., m} is divided into k k classes, at least one class contains l + 1 l+1 numbers which form an arithmetic progression. We denote the least number m m possessing this property by W ( k , l ) W(k, l) and call it the van der Waerden number. The question is equivalent to asking for the van der Waerden number W ( 2 , 3 ) W(2, 3) , which is 9.

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