Columnar Multiplication?

0. 1 6 6 6 6 × 0. 3 3 3 3 3 0. 0 \large{\begin{array}{cccccc} &0.& 1 & 6& 6 & 6&6& \ldots\\ \times&0. & 3 & 3& 3 & 3&3&\ldots\\ \hline &0. &0 &\bigstar &\bigstar& \bigstar& \bigstar&\ldots\\ \hline \end{array}}

The above shows the product of the two fractions 1 6 \dfrac16 and 1 3 \dfrac13 when written in decimal representation.

Find the value that represents the symbol \bigstar .

3 4 5 6

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3 solutions

Chung Kevin
Apr 15, 2016

The product of the fractions 1 6 \dfrac16 and 1 3 \dfrac13 is simply 1 × 1 6 × 3 = 1 18 \dfrac{1\times1}{6\times3} = \dfrac1{18} .

The long multiplication given in question tells us that 0.0 = 1 18 0.0\bigstar\bigstar\bigstar\bigstar\ldots = \dfrac1{18} .

Before we substitute them, let us convert this non-terminating decimal into a simple form first.

0.0 = 0.0 + 0.00 + 0.000 + 0.0000 + 0.0\bigstar\bigstar\bigstar\bigstar\ldots = 0.0\bigstar + 0.00\bigstar + 0.000\bigstar + 0.0000\bigstar + \cdots

The expression above represents a geometric progression sum with first term a = 0.0 = 100 a = 0.0\bigstar = \dfrac{\bigstar}{100} and common ratio r = 1 10 r = \dfrac1{10} . This sum is equal to a 1 r = 90 \dfrac a{1-r} = \dfrac\bigstar{90} .

We have 90 = 1 18 = 1 × 5 18 × 5 = 5 90 \dfrac\bigstar{90} = \dfrac1{18} = \dfrac{1\times5}{18\times5} = \dfrac5{90} , so = 5 \bigstar =\boxed5 .

I mean, sure, you can convert the decimal to a "simple" form and then use a geometric progression sum and common ratios and divide by 90... Or you could use long division.

Alex Li - 5 years, 1 month ago
Jesse Nieminen
May 5, 2016

1 3 × 1 6 = 1 2 × 1 9 = 0.5 × 0. 1 = 0.0 5 = 5 \frac{1}{3} \times \frac{1}{6} = \frac{1}{2} \times \frac{1}{9} = 0.5 \times 0.\overline{1} = 0.0\overline{5} \Rightarrow \bigstar = \boxed{5}

Moderator note:

Nice approach, converting into fraction form. That is often the best way of interpreting these repeating decimals.

Munem Shahriar
Dec 19, 2017

1 6 × 1 3 = 1 18 0.0 5 \dfrac 16 \times \dfrac 13 = \dfrac 1{18} \approx 0.0\overline{5}

= 5 \bigstar = 5

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