The least value of the positive integer for which is not an integer , is
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1000/13 = 76 + remainder 12 ie 76 multiples of 13 in number belonging to set (0,1000) Furthermore, 169 is multiple of 13 but contains other factor also as 13. so it has to be counted as well so what we can do is 1000/169 = 5 + remainder 155 total 13 available in 1000! is 76+5
81.
so 82th division will not be givin an integer.