Combi offer! #4

6 cards and 6 envelopes are numbered 1 , 2 , 3 , 4 , 5 , 6. Cards are to be placed in envelopes such that card number 1 is always placed in envelope number 2 and no card is placed in the envelope bearing same number. Find total number of ways to arrange the cards in envelopes?

265 53 67 264

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1 solution

The number of derangements of 6 distinct items is 265. Of these derangements, 1 5 \frac{1}{5} of them will involve card number 1 being place in envelope number 2.

Thus the solution is 1 5 265 = 53 \frac{1}{5} * 265 = \boxed{53} .

You can read about derangements here: link

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