Combination

Find the value of 47 C 4 + i = 1 5 52 i C 3 ^{47}C_4 + \displaystyle \sum_{i=1}^5 {}^{52-i} C_{3} , where n C r = n ! r ! ( n r ) ! ^nC_r\ = \dfrac {n!}{r!(n-r)!} is the binomial coefficient .

277534 455327 599936 270725

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1 solution

Khushi Mehta
Nov 26, 2016

nCr +nCr+1 =n+1Cr+1. Using this we get 52C4. Which is 270725

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