Combination.
Probability
Level
2
In an examination, there are three multiple choice questions and each question has 4 choices. Number of ways in which a student can fail to get all answer correct is -
27
4
63
24
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
1 solution
Total number of choices for each question - 4
No. of ways answering the all the 3 questions = 4x4x4 = 4^3 = 64.
No. of ways of correct answering (1 correct answer for each question) = 1x1x1 = 1
Total number of ways he may fail to answer all the questions correct = total number of ways of answering - correct ways = 64 - 1 = 63