Combinatorics

Probability Level 2

How many ways can you choose 12 doughnuts from 20 different types (assuming there are at least 12 of each type)?

C(20+1-12,20) C(1+20+12-20) C(20+12-1,20) C(12-20+1,20)

Prerna Chadha by Prerna Chadha , 29, India

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2 solutions

won't the solution be C(20+12-1,19) ??

1 Helpful 0 Interesting 0 Brilliant 0 Confused

Yes, the correct answer is C(20+12-1,19).

Jon Haussmann - 6 years, 9 months ago

Yes, I also think it should be C ( 20 + 12 − 1 , 19 ) C(20+12-1,19)

Raushan Sharma - 5 years, 9 months ago
Abdul Rakib
May 25, 2014

just put the numbers in c(n + r - 1, n)

0 Helpful 0 Interesting 0 Brilliant 0 Confused

wats the answer then.?

Prerna Chadha - 7 years ago

C(20+12-1,20)

Abdul Rakib - 7 years ago

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