Combinatorics Problem IV by Pr. Fares Salem

At a party there are 75 people. Everybody shakes everybody’s hand once. How often are hands shaken in total? Hint: How many people are involved in shaking hands?


The answer is 2775.

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3 solutions

Fares Salem
Oct 18, 2014

You want to find the number of all possible pairs of party guests. This is simply 75C2 = 2775.

Hands shaken in total = no. of sides + no. of diagonals in a 75-sided polygon = n + n(n-3)/2 ; where n=75 = 2775

Mohit Khanwale
Feb 6, 2015

75×37 = 2775

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