Fifteen dots are evenly spaced on the circumference of a circle. How many combinations of three dots can we pick from these 15 that do not form an equilateral triangle?
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First by ignoring the question. Lets first find the total number of triangles formed.
Total Triangles Formed = C ( 3 1 5 ) = 1 2 ! × 3 ! 1 5 ! = 1 × 2 × 3 1 5 × 1 4 × 1 3 = 4 5 5 .
So there are 4 5 5 triangles we can draw using 15 dots on a circle.
And now if we come to equilateral triangle. We know that all the dots are equally spaced. Suppose the points are numbers from 1 to 15. From point 1 to point 6 is one-third of the circle — again, from point 6 to point 11, and from point 11 back to point 1. That’s one equilateral triangle.
So, We could make an equilateral triangle using points ( 1 , 6 , 1 1 ) ; ( 2 , 7 , 1 2 ) ; ( 3 , 8 , 1 3 ) ; ( 4 , 9 , 1 4 ) ; ( 5 , 1 0 , 1 5 )
Therefore, There are only five equilateral triangles formed.
Number of Triangles formed = 4 5 5 − 5 = 4 5 0 .