When propane, a 3-Carbon alkane, is combusted, what is the theoretical mole ratio of Oxygen gas consumed to water produced?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Alkanes are hydrocarbons, elements with only Carbon and Hydrogen, that have the empirical formula CnH2n+1. Therefore, a three-Carbon hydrocarbon would have the molecular formula C3H8. When combusted with Oxygen, water and Carbon dioxide are produced, as is the case in all combustion reactions with Oxygen and hydrocarbons. Therefore, by balancing the resulting chemical equation, the ratios of reactants and products can be determined to be 5 moles of Oxygen per 4 moles of water.