Evaluate: ∫ − π π ln ( x 2 + e ) n = 1 ∑ 9 sin ( n x ) d x
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
I = ∫ − π π ln ( x 2 + e ) ∑ n = 1 9 sin ( n x ) d x = n = 1 ∑ 9 ∫ − π π ln ( x 2 + e ) sin ( n x ) d x = n = 1 ∑ 9 0 = 0 Note that sin ( n x ) is odd and ln ( x 2 + e ) is even, therefore the integrand ln ( x 2 + e ) sin ( n x ) is odd.
Problem Loading...
Note Loading...
Set Loading...
Sine is an odd function. Sum of several odd functions is odd. Dividing it by an even function leaves the function odd.
Integral of an odd function over an interval symmetrical with respect to the origin is zero.