Least common multiple

Algebra Level 2

If the product of two monomials is 72 x 5 72x^5 and their greatest common divisor is 6 x 2 6x^2 , what is their lowest common multiple ?

12 x 3 12x^3 12 x 2 12x^2 6 x 2 6x^2 10 x 3 10x^3

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1 solution

Marta Reece
Jun 4, 2017

Product of two monomials A A and B B is

A B = 72 x 5 AB=72x^5

Their greatest common divisor is 6 x 2 6x^2 , so they can be written as

A = a × 6 x 2 A=a\times 6x^2

B = b × 6 x 2 B=b\times 6x^2

And the product then is A B = a b ( 6 x 2 ) 2 = 36 a b x 4 AB=ab(6x^2)^2=36abx^4

which has to be equal to 72 x 5 72x^5 , giving us an equation for a b ab

36 x 4 a b = 72 x 5 36x^4ab=72x^5

with the solution

a b = 2 x ab=2x

There is not enough information to obtain a a and b b , and therefore A A and B B , individually, but their least common multiple will be

2 x × 6 x 2 = 12 x 3 2x\times6x^2=\boxed{12x^3}

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