The least common multiple of 2 × 3 × 5 and N is 2 × 3 2 × 5 × 7 . What is the smallest possible value of N ?
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Great explanation of finding N from the factors that we require.
nice logic used
You can also use the identity g cd ( a , b ) ∗ lcm ( a , b ) = a b .
Para encontrarmos o MMC entre dois números fatorizados: - pegamos os fatores incomuns; - e, os maiores expoentes dos fatores comuns.
Como o enunciado pede que calculemos o menor valor possível,...
{ 2 × 3 × 5 3 2 × 7 − − − − − − − − 2 × 3 2 × 5 × 7
Daí,
N = 3 2 × 7 N = 6 3
You need to explain more about how you got to the fact that 3^2*7=63
This however means that the number they give you is smaller than 2x3x5xN which is not a least common multiple.
I don't agree with this. If you look again at the first equation, its product will be of 30N. If we are going with N = 63, then it'll be 1890. The problem: The least common multiple of 2×3×5 and N is 2×3^2×5×7. Which means the least is 630; three times smaller than 1890.
So by going with this logic, N should be of N = 630/30, which is 21. Not 63.
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but, axb=gcd(a,b)x lcm(a,b)
gcd(30,63)=3.
so, 30xN=30x63=1890 and gcd(a,b) x lcm(a,b) = 3x630=1890. So, the solution is correct.
The answer is correct since it is the LCM of 2 different digits (2 3 5) and N. Therefore,it is the LCM of 30 and N..
the least common multiply is 2 x 3^2 x 5 x 7 one of the number is 2 x 3 x 5 In finding least common multiply, we must use all of the numbers with the biggest power or degree So, the smallest number of N is 3^2 x 7
The least common multiple is 2 × 3 2 × 5 × 7
Now therefore,
Therefore, the smallest possible value of N is 9x7=63
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As we are given that 2 X 3 X 5 and N has LCM as 2 x 3 2 x 5 x 7 and LCM means highest powers of factors in all the 4 number since 3 2 and 7 does not appear in prime factorization of 2, 3, 5 therefore N= 3 2 X 7 = 63