Common sense!

Number Theory Level 1

'A' and 'b' are two numbers , such that 'A' is not equal to 'B'. If Ax = Bx where x is a constant then find the value of x.


The answer is 0.

Mayank Prakash by Mayank Prakash , 21, India

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6 solutions

Mayank Prakash
Sep 30, 2014

As we know that, if we multiply 0 with any number then the product is always 0. Therefore if we assume that x=0 , then both LHS and RHS will equal to 0 , and hence will be equal. Common sense!!

2 Helpful 0 Interesting 0 Brilliant 0 Confused
Martin Nikolov
Dec 9, 2014

We have: Ax=Bx

x(A-B)=0, therefore x=0 since A is not equal to B

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Timothy Makambwa
Nov 6, 2014

Ax=Bx so it follows that Ax-Bx=0,Factorising x(A-B)=0,then x=0/(A-B)which is equal to 0

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Christian Ndaye
Oct 29, 2014

We all know that multiplying 0 with any other number, the product is always and it will be always 0. In this question, we are assuming that x=0 so if A and B are not equal numbers by multiplying them by 0 makes them equal. As simple as that.

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Saptarshi Roy
Oct 27, 2014

so easy and boring ans is 0

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Christian Daang
Oct 21, 2014

If A =/= B,

Ax = Bx

Ax - Bx = 0

x(A-B) = 0

x = 0 and A = B

But, as we say a while ago, A =/= B , then reject A = B

then,

the only value of x that is compatible is 0.

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