Common Sense is required here... :)
Algebra
Level
2
Suppose a and b are real numbers that satisfy a =/= b,
a + 3b = b^2 and b + 3a = a^2.
Find a + b.
The answer is 2.
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Given:
a+3b = b^2
b+3a = a^2
2(b-a) = (b+a)(b-a) ---->(b-a)(2-b-a) = 0
Since b = a is not allowed, then,
2-b-a = 0 ---> a+b = 2
Final Answer: 2.
"Too Short solution right? That's why, I said, use your common sense..."