IN a sequence 1, 7, 13, 19, ... so on so that each number is 6 more than the previous number. The next sequence being 1, 9, 17, 25, .... so on so that each number is 8 more than the preceding term. THe two sequences have infinite common numbers. FInd the first 3 common numbers.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
No explanations have been posted yet. Check back later!