Common tangent

Geometry Level 4

P 1 : y = x 2 ( 6 + 2 5 ) x + ( 22 + 6 5 ) P 2 : y = x 2 + ( 6 + 2 5 ) x ( 6 + 6 5 ) \begin{aligned} P_1 &: y = x^2 - ( 6 + 2 \sqrt{5} ) x + ( 22 + 6 \sqrt{5} ) \\ P_2 &: y = -x^2 + ( 6 + 2 \sqrt{5} ) x - ( 6 + 6 \sqrt{5} ) \end{aligned}

If the equation of the common tangent of the two parabolas P 1 P_1 and P 2 P_2 above is given by L : a x + b y + c = 0 L : ax+by+c=0 , where a , b 0 a,b \ge 0 and b |b| and c |c| are coprime, find a + b + c a+b+c .


The answer is -7.

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1 solution

Draw the graphs of both the curves,

You will notice that they are mirror images about the line y = 8 y=8 ,

One being above y = 8 y=8 and other being below y = 8 y=8 line,

So therefore we can conclude that y = 8 y=8 is the common tangent for both the curves.

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