Commutator Practice

Compute the commutator of operators [ x ^ 2 , p ^ ] [\hat{x}^2,\hat{p}] , where p ^ = i x \hat{p} = -i\hbar \partial_x is the momentum operator and x ^ \hat{x} is the position operator.

i p i\hbar p i i\hbar 2 i x 2i\hbar x i x i\hbar x

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1 solution

Matt DeCross
Mar 11, 2016

One can rewrite this commutator in terms of the canonical commutator:

[ x 2 , p ] = x x p p x x = x x p x p x + x p x p x x = x [ x , p ] + [ x , p ] x = 2 i x . [x^2,p]=xxp-pxx=xxp-xpx+xpx-pxx=x[x,p]+[x,p]x= 2i\hbar x.

Hats have been omitted, but all x x and p p above are operators. In the last equality the canonical commutation relation was used.

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