Comparable Square Form

Algebra Level 2

True or false :

$\quad$ If $a^2>b^2$ then $a>b$ must be true.

True False

2 solutions

Mostakim Shakil
Feb 17, 2016

For all the Positive integer this statement , when a>b ; $a^{2} > b^{2}$ is true. but in case of negative number this Statement is false as we know every sqrt gives us two root values, one of which is negative. Like a = -2 and b= -3 , as always here a>b. But their squared value $a^{2}$ = 4 and $b^{2}$ =9 ,thus $a^{2}$ < $b^{2}$ .

Mehul Arora
Feb 17, 2016

$\huge {(-2)^2 <(-3)^2, (-2)>(-3)}$

Comparable Square Form

2 solutions

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