How Do I Compare Their Densities?

An object is put in turn , in three liquids having different densities. The object floats with 3 5 , 2 9 , 8 11 \dfrac 35 ,\dfrac 29 , \dfrac8{11} parts of its volume inside the liquid surface in liquids of densities A , B A , B and C C respectively.

Which of the following gives the correct relation between A , B A , B and C C ?

C > B > A C>B>A C < A < B C<A<B C > A > B C>A>B C < B < A C<B<A

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1 solution

Let the total volume of the submerged body be V V and let it's density be σ \sigma . Let the densities of the three liquids be ρ A {\rho}_{A} , ρ B {\rho}_{B} and ρ C {\rho}_{C} respectively. Using Archimedes' principle and the equation of buoyancy, we get:

σ V g = 3 5 V ρ A g \sigma V g = \frac {3}{5} V {\rho}_{A} g

and, σ V g = 2 9 V ρ B g \sigma V g = \frac {2}{9} V {\rho}_{B} g

and also, σ V g = 8 11 V ρ C g \sigma V g = \frac {8}{11} V {\rho}_{C} g

Now, solving for ρ A {\rho}_{A} , ρ B {\rho}_{B} and ρ C {\rho}_{C} , we get:

ρ A = 5 3 σ {\rho}_{A} = \frac {5}{3} \sigma

ρ B = 9 2 σ {\rho}_{B} = \frac {9}{2} \sigma

ρ C = 11 8 σ {\rho}_{C} = \frac {11}{8} \sigma

which shows ρ B > ρ A > ρ C {\rho}_{B} > {\rho}_{A} > {\rho}_{C}

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