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Geometry Level 2

Which of the following is true?

(A) cos 22 1 o > sin 31 9 o \cos221^o>\sin319^o

(B) cos 13 9 o > sin 22 1 o \cos139^o>\sin221^o

(C) sin 13 9 o > cos 4 1 o \sin139^o>\cos41^o

(D) sin 22 1 o > cos 13 9 o \sin221^o>\cos139^o

(E) sin 4 1 o > cos 31 9 o \sin41^o>\cos319^o


This is a part of the Set .

E A D B C

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1 solution

First, we have f ( x ) = sin x f(x)=\sin x increases on ( 0 o , 9 0 o ) (0^o, 90^o) and g ( x ) g(x) decreases on ( 0 o , 9 0 o ) (0^o, 90^o) , so sin 4 1 o < sin 4 5 o = cos 4 5 o < cos 4 1 o \sin41^o<\sin45^o=\cos45^o<\cos41^o .

We have:

(A) cos 22 1 o > sin 31 9 o cos 4 1 o > sin 4 1 o sin 4 1 o > cos 4 1 o \cos221^o>\sin319^o \Leftrightarrow -\cos41^o>-\sin41^o \Leftrightarrow \sin41^o>\cos41^o , which is not true.

(B) cos 13 9 o > sin 22 1 o cos 4 1 o > sin 4 1 o sin 4 1 o > cos 4 1 o \cos139^o>\sin221^o\Leftrightarrow -\cos41^o>-\sin41^o \Leftrightarrow \sin41^o>\cos41^o , which is not true.

(C) sin 13 9 o > cos 4 1 o sin 4 1 o > cos 4 1 o \sin139^o>\cos41^o\Leftrightarrow \sin41^o>\cos41^o , which is not true.

(D) sin 22 1 o > cos 13 9 o sin 4 1 o > cos 4 1 o sin 4 1 o < cos 4 1 o \sin221^o>\cos139^o\Leftrightarrow -\sin41^o>-\cos41^o \Leftrightarrow \sin41^o<\cos41^o , which is true .

(E) sin 4 1 o > cos 31 9 o sin 4 1 o > cos 4 1 o \sin41^o>\cos319^o\Leftrightarrow \sin41^o>\cos41^o , which is not true.

So the correct answer is D \boxed{D} .

You had missed to mentioned g ( x ) = cos x g(x) =\cos x as it is decreasing in the interval ( 0 ° , 90 ° ) \,(0°,90°) . :)

Naren Bhandari - 3 years, 1 month ago

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