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First, we have f ( x ) = sin x increases on ( 0 o , 9 0 o ) and g ( x ) decreases on ( 0 o , 9 0 o ) , so sin 4 1 o < sin 4 5 o = cos 4 5 o < cos 4 1 o .
We have:
(A) cos 2 2 1 o > sin 3 1 9 o ⇔ − cos 4 1 o > − sin 4 1 o ⇔ sin 4 1 o > cos 4 1 o , which is not true.
(B) cos 1 3 9 o > sin 2 2 1 o ⇔ − cos 4 1 o > − sin 4 1 o ⇔ sin 4 1 o > cos 4 1 o , which is not true.
(C) sin 1 3 9 o > cos 4 1 o ⇔ sin 4 1 o > cos 4 1 o , which is not true.
(D) sin 2 2 1 o > cos 1 3 9 o ⇔ − sin 4 1 o > − cos 4 1 o ⇔ sin 4 1 o < cos 4 1 o , which is true .
(E) sin 4 1 o > cos 3 1 9 o ⇔ sin 4 1 o > cos 4 1 o , which is not true.
So the correct answer is D .