Complex Complex Equations

Algebra Level 4

Given z = cos ( 2 π 2 n + 1 ) + i sin ( 2 π 2 n + 1 ) z=\cos(\frac{2\pi}{2n+1})+i\sin(\frac{2\pi}{2n+1}) ,where n is a positive integer,find the equation whose roots are α = z + z 3 + z 5 + . . . + z 2 n 1 \alpha=z+z^3+z^5+...+z^{2n-1} and β = z 2 + z 4 + z 6 + . . . + z 2 n \beta=z^2+z^4+z^6+...+z^{2n} .

The equation will be of form: x 2 + x + 1 k s e c 2 ( π 2 n + 1 ) x^2+x+\frac{1}{k}sec^2(\frac{\pi}{2n+1}) What is k?

2 8 1 4

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1 solution

Here's the hint :-P!Well much more of an answer i'd say!

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