Complex Cubic
Consider the following complex cubic equation:
\[\begin{array} {} A \alpha^3 + B \alpha^2 + C\alpha + D = 0 \\ A = 7 - 3 j \\ B = 0 + 1 j \\ C = 2 + 4 j \\ D = 5 + 0 j \\ j = \sqrt{-1}\end{array} \]
The three complex roots of this equation form the vertices of a triangle when plotted in the complex plane. What is the area of the triangle?
The answer is 0.931633.
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