Complex or Simplex?

Algebra Level 5

1 + 4 + 16 + 64 + 1 4 16 64 \sqrt{-1+\sqrt{-4+\sqrt{-16+\sqrt{-64+\sqrt{\dots}}}}}\cdot \sqrt{-1-\sqrt{-4-\sqrt{-16-\sqrt{-64-\sqrt{\dots}}}}} The expression above can be written as a + b i a+bi , where a , b a,b are real numbers .

Find the value of a + b a+b .


Clarification: i = 1 i=\sqrt{-1} .


The answer is -2.

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1 solution

x + 1 = x 2 + 2 x + 1 = x 2 + 4 x 2 + 4 x + 1 x+1=\sqrt{x^2+2x+1}=\sqrt{x^2+\sqrt{4x^2+4x+1}} = x 2 + 4 x 2 + 16 x 2 + 8 x + 1 = x 2 + 4 x 2 + 16 x 2 + 64 x 2 + =\sqrt{x^2+\sqrt{4x^2+\sqrt{16x^2+8x+1}}}=\sqrt{x^2+\sqrt{4x^2+\sqrt{16x^2+\sqrt{64x^2+\sqrt{\dots}}}}} And x 1 = x 2 2 x + 1 = x 2 4 x 2 4 x + 1 = x-1=\sqrt{x^2-2x+1}=\sqrt{x^2-\sqrt{4x^2-4x+1}}=\cdots = x 2 4 x 2 16 x 2 64 x 2 =\sqrt{x^2-\sqrt{4x^2-\sqrt{16x^2-\sqrt{64x^2-\sqrt{\dots}}}}} So, replacing x = i x=i we can find out that the expression is the same that ( i + 1 ) ( i 1 ) = i 2 1 = 2 (i+1)(i-1)=i^2-1=-2

I'm sorry, i know that the value of the expression is -2, but does it mean that the value of a + b a+b is -2? The problem ask about the value of a + b a+b . So, i think a + b 2 a+b \neq -2

Fidel Simanjuntak - 3 years, 10 months ago

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@Fidel Simanjuntak , as the expression equals 2 -2 and can be written as a complex number, we have a + b i = 2 a+bi=-2 and so we know b = 0 a = 2 a + b = 2 b=0 \wedge a=-2 \Rightarrow a+b=-2

Hjalmar Orellana Soto - 3 years, 10 months ago

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Oh, okay.. I didn't concern that b = 0 b=0 .. Hahahahaha

Fidel Simanjuntak - 3 years, 10 months ago

I'm sorry to be 3 years and a half late, but a = 2 a=-2 and b = 0 b=0 , so we're asked about a + b = 2 + 0 = 2 a+b=-2+0=-2

Hjalmar Orellana Soto - 3 months, 3 weeks ago

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